Respuesta :
That is a geometric sequence of the form a(n)=-3(1/2)^(n-1)
The sum of any geometric sequence is:
s(n)=a(1-r^n)/(1-r)
and if r^2<1 it converges to a sum of:
s=a/(1-r).... in this case:
s=-3/(1-1/2)
s=-3/(1/2)
s=-6
The sum of any geometric sequence is:
s(n)=a(1-r^n)/(1-r)
and if r^2<1 it converges to a sum of:
s=a/(1-r).... in this case:
s=-3/(1-1/2)
s=-3/(1/2)
s=-6