Simple...
you have: [tex]2 x^{2} +6x=5[/tex]
Remember, you must first move all terms to the left to reduce.
--->>
[tex] 2x^{2} +6-5=0
[/tex]
Using [tex] (\frac{b}{2} ) ^{2} [/tex] in order to create a new term, and then solve for x by completing the square with this term-->>
x= [tex]- \frac{3}{2}, (+/-) \frac{ \sqrt{19} }{2} [/tex]
Thus, your answer.
