The probability that at least one of them is a 1 is 0.2778 when a fair set of dice is thrown and the total of the numbers falling above them is even.
Given that,
A fair set of dice is thrown.
We have to find given that the total of the numbers falling above them is even, what is the probability that at least one of them is a 1.
We know that,
A fair set of dice is thrown.
The total of the numbers falling above them is even.
The probability that at least one of them is a 1 is
(5/36)/(8/36)
5/18
0.2778
Therefore, The probability that at least one of them is a 1 is 0.2778 when a fair set of dice is thrown and the total of the numbers falling above them is even.
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