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Sleep experts believe that sleep apnea is more likely to occur in men than in the general population. In other words, they CLAIM that the percentage of men who suffer from sleep apnea is greater than 8%. To test this claim, one sleep expert interviews 75 men and determines that 10 of the men suffer from sleep apnea.
test statistic z=?
calculate P-value P= ? (2 decimal)
What is the decision at the 5% Significance Level (Sleep experts believe that sleep apnea is more lik) Reject or fail to reject?
What is your conclusion? support or not?
possible error type I or II

Respuesta :

rafikiedu08

Establish Null Hypothesis, H0:P=0.08 Alternative, greater than 8% of men suffer from sleep apnea and support or not the possible error type I or II, Type I Error.

H1: No. of Success Chances Observed (x)=10 Test Statistic P>0.08

There are 75 objects in the sample, which is given.

Number of Successes Rate (P)=x/n= 10/75= 0.1333

Failure Probability (Q0) = 0.92, Success Probability (Po) = 0.08

To test a single proportion, we utilize Test Statistics,

(Z) = P-Po/Sqrt(PoQo/n)

Z0= 0.13333-0.08/(Sqrt(0.0736)/75)

Z0 = 1.7025\s| Zo| = 1.7025

Critical Value

The value of |Z| at LOS 0.05% is 1.64; we calculated it by using the formulas |Z0| = 1.70 & |Z | =1.64; as a result, we reject.

H0

Right Tail - Ha: P-Value ( P > 1.70251 ) = 0.04433

Therefore, as P(0.05) > 0.04433, we reject H0.

The Pvalue for z= 1.7025 is 0.04433.

Reject or fail to reject is the choice at the 5 percent of significance Level.

We support decision possible error type I or II, Type I Error.

To learn more about probability visit: https://brainly.com/question/11234923

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