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c8 q8 v1: a random sample of 100 students is taken from a larger population of students in a multi-lecture course and the sample mean (average) of their final grades is found to be 62.25. suppose that the population standard deviation is known to be 4.5. which of the following is correct? (note that you can answer these questions from understanding gleaned in lecture and lab, but may find r helpful.)

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varshamittal029

99.7% of the students scored between (44.67 , 56.33) i.e.

between 44 and 56.

Given, the mean of the final grades of the sample be 62.25 and the standard deviation be 4.5

On Subtracting 1 from your sample size, we get

100 – 1 = 99.

On Subtracting confidence level from 1, and then divide by two.

(1 – .997) / 2 = 0.0015

Now, df = 99 and α = 0.0015

from the table at df = 99 we got 2.262.

Divide your sample standard deviation by the square root of your sample size.

28 / √(100) = 2.8

Now, 2.262 × 2.8 = 6.33

So, the confidence interval be,

(100 - 6.33 , 100 + 6.33) = (44.67 , 56.33)

Hence, 99.7% of the students scored between (44.67 , 56.33) i.e.

between 44 and 56.

Learn more about Statistics here https://brainly.com/question/27165606

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