A transport plane takes off from a level landing field with two gliders in tow, one behind the other. The mass of each glider is 700 kg, and the total resistance (air drag plus friction with the runway) on each may be assumed constant and equal to 2,500 N. The tension in the tow rope between the transport plane and the first glider is not to exceed 12,000 N.
What is the tension in the tow rope between the two gliders while they are accelerating for the takeoff?

Respuesta :

The second law of Newton and kinematics allows to find the answers for the distance and tension are: The distance traveled is 133.3 m

kinematics studies the movement of bodies establishing relationships between the position, velocity and acceleration of bodies

              v² = [tex]vo^{2}[/tex] + 2ax

Where v is the velocity, v₀ the initial velocity, a the acceleration and x the distance traveled,

We look for the acceleration that the system has using Newton's second law,

Glider 1

x-axis

         T₁ - T₂ - fr. = m a

y-axis  

        N₁ - W = 0

        N₁ = W

Glider 2

x-axis

        T₂ -fr = m a

y-axis  

        N₂ - W =0

        N₂ = W

We write the system of equations

T₁ - T₂ -fr  = m a

             T₂ - fr = m a

We solve the system

        T₁ - 2 fr = 2 m a

        a = T1 - 2fr /2m

Indicates that the friction force for each glider is 1600 N

Calculate

        a = 12000 - 3600 / 1400

        a = 6 m / s²

Taking the acceleration we can use the kinematics relationship to find the distance traveled

  v² = [tex]vo^{2}[/tex] + 2ax

As part of rest the initial velocity is zero

          v² = 0 + 2 ax

          x = v² / 2 a

indicate that the speed of 40 { m/s} is required for takeoff

          x = 1600 / 12

          x = 133.33m

Learn more about kinematics here: https://brainly.com/question/7590442

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