The second law of Newton and kinematics allows to find the answers for the distance and tension are: The distance traveled is 133.3 m
kinematics studies the movement of bodies establishing relationships between the position, velocity and acceleration of bodies
v² = [tex]vo^{2}[/tex] + 2ax
Where v is the velocity, v₀ the initial velocity, a the acceleration and x the distance traveled,
We look for the acceleration that the system has using Newton's second law,
Glider 1
x-axis
T₁ - T₂ - fr. = m a
y-axis
N₁ - W = 0
N₁ = W
Glider 2
x-axis
T₂ -fr = m a
y-axis
N₂ - W =0
N₂ = W
We write the system of equations
T₁ - T₂ -fr = m a
T₂ - fr = m a
We solve the system
T₁ - 2 fr = 2 m a
a = T1 - 2fr /2m
Indicates that the friction force for each glider is 1600 N
Calculate
a = 12000 - 3600 / 1400
a = 6 m / s²
Taking the acceleration we can use the kinematics relationship to find the distance traveled
v² = [tex]vo^{2}[/tex] + 2ax
As part of rest the initial velocity is zero
v² = 0 + 2 ax
x = v² / 2 a
indicate that the speed of 40 { m/s} is required for takeoff
x = 1600 / 12
x = 133.33m
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