Toilet bowl cleaner contain hydrochloric acid, which dissolves calcium carbonate in a toilet bowl. The mass of calcium carbonate dissolved is 5.28g.
To find out the mass, first write the balanced reaction. The balanced reaction between calcium carbonate and hydrochloric acid is
CaCO₃+2HCl→CaCl₂+H₂O+CO₂
The molar mass of HCl is 36g/mol. Hence, the number of moles for HCl is
moles=3.8 g×(1 mol/36 g)
moles=0.1055 mol
Using moles of HCl, find out moles of CaCO₃. Since mol to mol ratio for HCl to CaCO₃ is 2:1. Therefore, moles of CaCO₃ required is
0.1055 mol HCl×(1 mol CaCO₃/2 mol HCl)
=0.05275 mol CaCO₃
Convert the above moles in the mass. The molar mass of CaCO₃ is
Molar mass=[40+12+(3×16)]g/mol
=(40+12+48)g/mol
=100 g/mol
Hence, the mass of CaCO₃ is
mass=0.05275 mol CaCO₃×(100 g CaCO₃/1 mol CaCO₃)
=5.275 g CaCO₃
=5.28g CaCO₃
Therefore, the mass of calcium carbonate(CaCO₃) dissolved by 3.8g of HCl is 5.28g.
To know more about balanced reactions
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