The ordered pair that is on the function y=f(2x+1)+3 is (-3/2, 6)
Here we know that for the function:
y = f(x)
And we know that the point (-2, 3) belongs to the function, this means that:
f(-2)= 3
Now we want to find a point on the function:
f(2x + 1) + 3
If we find x such that:
2x + 1 = -2
2x = -3
x = -3/2
Now we can evaluate the function in that value of x to get:
y = f(2*-3/2 + 1) + 3
y = f(-2) + 3
y = 3 + 3
y = 6
Then we have the point (-3/2, 6) on the function.
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