Solution of the system of linear equation 3a + 6b = 45 , 2a -2b = -12 is equal to a = 1 and b =7.
As given in the question,
System of linear equation are:
3a + 6b = 45 __( 1 )
2a - 2b = -12 __(2 )
Solution of the linear equation by elimination method is given by:
Multiply ( 2 ) by 3 and add it to (1) we get,
3a + 6b = 45
6a - 6b = -36
9a = 9
⇒ a = 1
Substitute the value of a = 1 in (1) we get,
3( 1 ) + 6b = 45
⇒ 6b = 42
⇒ b = 7
Therefore, the solution of the system of linear equation is a = 1 and
b =7.
The complete question is :
What is the solution (a, b) to this system of linear equations?
3a+6b = 45 , 2a-2b = -12
a. (-27, 6)
b. (-1, 7)
c. (1, 7)
d. (27, -6)
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