Given that the number of turns of the coil is n = 325
The length is l = 510 mm = 0.51 m
The flux density is B = 0.033 T
The speed of the conductor is v = 15.2 m/s
The maximum induced emf will be
[tex]\begin{gathered} e_{\max }=nBlv\sin 90^{\circ} \\ =325\times0.033\times0.51\times15.2\times1 \\ =83.1402\text{ V} \end{gathered}[/tex]
The emf when the angle is 40 degrees will be
[tex]\begin{gathered} e=nBlvsin40^{\circ} \\ =325\times0.033\times0.51\times15.2\times0.643 \\ =\text{ 53.46 V} \end{gathered}[/tex]
