1) Considering that softball a sphere, we can find its volume by using the following formula:
[tex]\begin{gathered} V=\frac{4}{3}\cdot\pi\cdot r^3 \\ \end{gathered}[/tex]2) But as the circumference has been given we can find the radius through that:
[tex]\begin{gathered} C=2\cdot\pi\cdot r \\ 12=2\cdot\pi\cdot r \\ \frac{12}{2\pi}=\frac{2\pi}{2\pi}\cdot r \\ r=\frac{6}{\pi} \end{gathered}[/tex]Now, we can plug into that the radius:
[tex]\begin{gathered} V=\frac{4}{3}\cdot\pi\cdot(\frac{6}{\pi}) \\ V=\frac{4}{3}\cdot6 \\ V=\frac{24}{3} \\ V=8in^3 \end{gathered}[/tex]3) Therefore the volume of that ball is 8 in³
