Answer:
B. X= -6 and x = 5
Explanation:
Given the function f(x) = x^2 + x - 30, the zeros occurs at f(x) = 0
x^2 + x - 30 = 0
Factorize;
x^2+6x-5x-30 = 0
x(x+6)-5(x+6) = 0
(x+6)(x-5) = 0
x+6 = 0 and x-5 = 0
x = -6 and 5
Hence the zeros of the equation is at x = -6 and x = 5
