Let the length of the rectangle be l and the width be w
width is 11 feet more than length: we can write:
w = 11 + l
Also , perimeter is 54, we can write:
2l + 2w = 54
Note: Perimeter is sum of all sides
Now,
we replace 1st equation in 2nd and find l:
[tex]\begin{gathered} 2l+2w=54 \\ 2l+2(11+l)=54 \\ 2l+22+2l=54 \\ 4l=54-22 \\ 4l=32 \\ l=\frac{32}{4} \\ l=8 \end{gathered}[/tex]w is 11 + l
So,
width is 11 + 8 = 19
Length = 8 feet
Width = 19 feet
