Given,
The maximum pressure that a human body can withstand, P=1.80×10⁵ Pa
The density of the seawater, ρ=1.03×10³ kg/m³
The acceleration due to gravity, g=9.8 m/s²
The pressure on a body under the water is given by,
[tex]P=p_a+\rho gh[/tex]
Where pₐ is the atmospheric pressure at the sea level and h is the safe depth that a human can dive into.
The value of the pressure at sea level is pₐ=1 atm=1.01×10⁵ Pa
On rearranging the above equation,
[tex]h=\frac{P-p_a}{\rho g}[/tex]
On substituting the known values,
[tex]\begin{gathered} h=\frac{1.80\times10^5-1.01\times10^5}{1.03\times10^3\times9.80} \\ =7.8\text{ m} \end{gathered}[/tex]
Therefore the maximum safe depth an average human can dive is 7.8 m
