Solution:
Given:
Since the bottom of the cylinder will not be painted and the top is spherical.
The top is a hemisphere. Hence, the surface area to be painted will be;
[tex]\begin{gathered} A=2\pi rh+2\pi r^2 \\ \\ where; \\ r=10in \\ h=26in \end{gathered}[/tex]
Hence,
[tex]\begin{gathered} A=(2\times\pi\times10\times26)+(2\times\pi\times10^2) \\ A=520\pi+200\pi \\ A=720\pi\text{ sq in} \end{gathered}[/tex]
Therfore, the surface area to be painted is ;
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