Thr equation of a line in Slope-Intercept form is:
[tex]y=mx+b[/tex]
Where "m" is the slope and "b" is the y-intercept.
You have this equation:
[tex]2x+y=8[/tex]
Solve for "y" in order to write it in Slope-Intercept form:
[tex]y=-2x+8[/tex]
You can see that the y-intercept is:
[tex]b=8[/tex]
Since "x" is zero when the line cuts the y-axis, you have this point:
[tex](0,8)[/tex]
You know that "y" is zero when the line cuts the x-axis. So to find the x-intercept, substitute that value of "y" into the equation and solve for "x":
[tex]\begin{gathered} 0=-2x+8 \\ \frac{-8}{-2}=x \\ \\ x=4 \end{gathered}[/tex]
So you also have this point:
[tex](4,0)[/tex]
Knowing these points, you can plot them of the Coordinate plane and graph the line.
The graph of the line is:
