OziasC627949 OziasC627949

31-10-2022
Chemistry

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How many moles of KI are present in 0.250 L of a 2.30M solution?a 0.575 molb. 0.109 molc. 9.20 mold 2.55 mol Please show work too

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AvreyH409951 AvreyH409951

31-10-2022

In this question we are given the volume as 0.250L and the concentration as 2.30 M

we are required to find the number of mols of KI and we can use the following equation M= n/L

when we rearange the formular and make n subject of the formula it becomes

n = MV

therefore

n = (2.30)(0.250)

= 0.575 mol

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