In Pleasantburg, 2,850 people pay taxes. Of these taxpayers, 1/6 pay between $10,000 and $20,000 in taxes per year, inclusive. How many taxpayers pay either more than $20,000 or less than $10,000 in taxes per year?

Note that the problem is asking for the number of taxpayers that pay either more than $20,000 or less than $10,000. In other words, they are asking for the complement fraction of 1/6. Remember that the complement fraction can be found by subtracting the fraction from 1.

[tex]1-\frac{1}{6}=\frac{6-1}{6}=\frac{5}{6}[/tex]

This means 5/6 of the taxpayers pay more than $20,000 or less than $10,000. Now let's multiply this fraction by the number of people.

[tex]\frac{5}{6}\cdot2,850=2,375[/tex]

In Pleasantburg, 2,850 people pay taxes. Of these taxpayers, 1/6 pay between $10,000 and $20,000 in taxes per year, inclusive. How many taxpayers pay either more than $20,000 or less than $10,000 in taxes per year?

Respuesta :

Therefore, 2,375 people pay taxes more than $20,000 or less than $10,000.

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