The standard form of expression equation of a straight line is;
[tex]y\text{ = mx+c}[/tex]where;
m is the slope
c is the intercept
Given
slope m = -3/8
Next is for us to get the y- intercept of the line. This is done by subtituting the slope and the point (0,10) given into the equation y = mx+c and calculating c as shown;
[tex]\begin{gathered} y\text{ = mx+c} \\ 10\text{ = -3/8(0)+c} \\ 10\text{ = 0+c} \\ c\text{ = 10} \end{gathered}[/tex]Next is to get the equation of the line by substituting m = -3.8 and c= 10 into the standard form of the equation as shown;
[tex]\begin{gathered} y\text{ = mx+c} \\ y\text{ = -}\frac{3}{8}x+10 \end{gathered}[/tex]Hence the first option is correct
