Respuesta :

given that

[tex]y=\frac{x+3}{2x+1}[/tex]

Differentiating we get

[tex]\begin{gathered} \frac{dy}{dx}=\frac{(2x+1)-2(x+3)_{}}{(2x+1)^2} \\ =\frac{2x+1-2x-6}{(2x+1)^2} \\ =\frac{-5}{(2x+1)^2} \end{gathered}[/tex]

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