Given data:
The given equation of the line is x+3y=3.
The given equation can be written as,
[tex]\begin{gathered} x+3y=3 \\ 3y=3-x \\ y=\frac{1}{3}(-x+3) \\ =-\frac{1}{3}x+1 \end{gathered}[/tex]The standard equation of the line is,
[tex]y=mx+c[/tex]Here, m is the slope.
Compare the given equation with the standard equation of the line.
m=-1/3
Thus, the slope of the line is -1/3.
