Two parallel lines are cut by a transversal as shown below.Suppose =m∠3132°. Find m∠5 and m∠8.

The angle 3 is given 132 degree.
To determine the angle 5 and angle 8.
Use the property that the sum of the corresponding interior angles is 180 degree.
[tex]\angle3+\angle8=180\degree[/tex]Substitute the values
[tex]\begin{gathered} 132\degree+\angle8=180\degree \\ \angle8=180\degree-132\degree \\ \angle8=48\degree \end{gathered}[/tex]And also from the figure,
The sum of angle 8 and 5 is 180 degree.
[tex]\begin{gathered} \angle8+\angle5=180\degree \\ \angle5=180\degree-48\degree \\ \angle5=132\degree \end{gathered}[/tex]Answer
Hence the angle 5 is 132 degree and angle 8 is 48 degree.