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Rewrite the following in logarithmic form:a) 6 to 3rd power (sorry my superscript short cut isn't working) = 216b) 10 to the 0 power =xc) e to the x power =28

Respuesta :

Part a

we have

[tex]6^3=216[/tex]

so

in logarithmic form

[tex]\log _6216=3[/tex]

Part b

[tex]10^0=x[/tex]

in logarithmic form

[tex]\begin{gathered} \log _{10}x=0 \\ \log x=0 \end{gathered}[/tex]

Part c

we have

[tex]e^x=28[/tex]

in logarithmic form

[tex]\ln 28=x[/tex]

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