Given the following expression:
[tex]\begin{gathered} V=Bh \\ \Rightarrow V=(113.04)\cdot(20) \end{gathered}[/tex]
Notice that the value of the area of the base is the following:
[tex]B=\pi\cdot r^2=113.04[/tex]
with pi = 3.14, we can solve for r to find the radius of the cylinder:
[tex]\begin{gathered} 3.14r^2=113.04 \\ \Rightarrow r^2=\frac{113.04}{3.14}=36 \\ \Rightarrow r=\sqrt[]{36}=6 \\ r=6 \end{gathered}[/tex]
therefore, the cylinder has radius 6 and height 20 (the correct model is C)
