Respuesta :
Given:
a.) Two buses leave a station at the same time and travel in opposite directions.
Let,
Speed of Bus A = s
Speed of Bus B = s + 15
b.) The two buses are 543 kilometers apart after 3 hours.
d = 543 km
t = 3 hrs.
We get,
[tex]\text{ (Speed Bus A)(t) + (Speed of Bus B)(t) = 543 km}[/tex][tex]\text{ (v)(3) + (v + 15)(3) = 543 km}[/tex][tex]\text{ }\frac{\text{(v)(3) + (v + 15)(3)}}{\text{ 3}}\text{ = }\frac{\text{543 km}}{\text{ 3}}[/tex][tex]\text{ v + v + 15 km/h = 181 km/h}[/tex][tex]\text{ 2v = 181 km/h - 15 km/h}[/tex][tex]\text{ 2v = 166 km/h}[/tex][tex]\text{ }\frac{\text{2v}}{\text{ 2}}\text{ = }\frac{\text{166 km/h}}{\text{ 2}}[/tex][tex]\text{ v = }83\text{ km/h}[/tex]Therefore,
the speed of the slower bus = 83 km/h
the speed of the faster bus = 83 km/h + 15 km/h = 98 km/h
