Respuesta :
Answer:
The probability that there is at least one infected person in group assigned for the task = 0.7
Explanation:Total number of crew members = 5
Number of infected persons = 2
Number of uninfected persons = 3
Probability that there is at least one infected person will be:
P(at least 1 infected) = P(1 infected) + P(2 infected)
Probability of selecting 1 infected person
[tex]\begin{gathered} P(1\text{ infected person\rparen=}\frac{2C1\times3C1}{5C2} \\ \\ P(1\text{ infected person\rparen =}\frac{2\times3}{10} \\ \\ P(1\text{ infected person\rparen =0.6} \end{gathered}[/tex][tex]\begin{gathered} P(2\text{ }\imaginaryI\text{nfected persons}\operatorname{\rparen}=\frac{\text{2C2}}{\text{5C2}} \\ \\ P(2\text{ infected persons\rparen =}\frac{1}{10} \\ \\ P(2\text{ infected persons\rparen = 0.1} \end{gathered}[/tex]P(at least 1 infected) = P(1 infected) + P(2 infected)
P(at least 1 infected) = 0.6 + 0.1
P(at least 1 infected) = 0.7
The probability that there is at least one infected person in group assigned for the task = 0.7
