The point-slope equation has the following form:
[tex](y-y_0)=s(x-x_0)[/tex]Where "s" is the slope and (x_0,y_0) is a point in the line.
So, given the slope of 1/2 and the point (6,-3), the point-slope form will be:
[tex]\begin{gathered} (y-(-3))=\frac{1}{2}(x-6) \\ (y+3)=\frac{1}{2}(x-6) \end{gathered}[/tex]