17 16 ✓ 15 ✓ 14 X 13 Ex la A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 96 m long and 58 m wide. m2 m Find the area of the training field. Use the value 3.14 for it, and do not round your answer. Be sure to include the correct unit in your answer. 96 m ? Х 58 m

Respuesta :

The total area will be, the area of the two semi circles plus the area of the rectangle, so:

Area of the first semi circle:

[tex]Ac1=\frac{\pi r^2}{2}=\frac{\pi(29^2)}{2}=\frac{841\pi}{2}m^2[/tex]

Area of the rectangle:

[tex]Ar=w\cdot l=96\cdot58=5568m^2[/tex]

Area of the second semi circle:

[tex]Ac2=Ac1=\frac{841\pi}{2}m^2[/tex]

So, the total area is:

[tex]A_T=\frac{841\pi}{2}m^2+5568m^2+\frac{841\pi}{2}=8208.74m^2[/tex]