Given:
[tex]\sec \text{ B=}\frac{\sqrt[]{117}}{9}[/tex][tex]\begin{gathered} AC=\sqrt[]{117-81} \\ AC=\sqrt[]{36} \\ AC=6 \end{gathered}[/tex][tex]\begin{gathered} \csc A=\frac{AB}{BC} \\ \csc A=\frac{\sqrt[]{117}}{9} \end{gathered}[/tex]
Option A is the final answer
