Answer:
60
Explanation:
Given the below expression;
[tex](11j^{-3}k^{-2})(j^3k^4)[/tex]
Applying the product rule, we'll have;
[tex]\begin{gathered} 11j^{-3+3}k^{-2+4} \\ =11j^0k^2 \\ =11k^{2^{}} \end{gathered}[/tex]
Let's go ahead and evaluate the above expression when k = 7;
[tex]\begin{gathered} 11\ast(7)^2 \\ =11+49 \\ =60 \end{gathered}[/tex]
