Explanation
The parabola in vertex form is given as
[tex]y=a(x-h)^2+k[/tex]Where (h,k) is the vertex.
[tex]y=a(x-0)^2+1[/tex]Therefore, since the parabola passes through (8,-3)
We will have;
[tex]\begin{gathered} -3=a(8)^2+1 \\ -3=64a+1 \\ 64a=-4 \\ a=-\frac{4}{64} \\ a=-\frac{1}{16} \end{gathered}[/tex]Therefore;
Answer:
[tex]y=-\frac{1}{16}(x-0)^2+1[/tex]