Explanation
If we look at the given options we can see that
[tex]\begin{gathered} \frac{1}{3}x-\frac{1}{4}y-\frac{4}{5}+\frac{1}{3}x-\frac{1}{4}y \\ rearrange\text{ terms} \\ =\frac{1}{3}x+\frac{1}{3}x-\frac{1}{4}y-\frac{1}{4}y-\frac{4}{5} \\ =\frac{x+x}{3}-\frac{y+y}{4}-\frac{4}{5} \\ =\frac{2x}{3}-\frac{2y}{4}-\frac{4}{5} \\ =\frac{2x}{3}-\frac{1}{2}y-\frac{4}{5} \end{gathered}[/tex]
Answer: Option 2
