ANSWER
[tex]10.67Ω[/tex]
EXPLANATION
First, we have to find the total resistance for the 4Ω and 10Ω resistors connected in series.
To do this, find the sum of the resistances:
[tex]4+10=14Ω[/tex]
This total resistance is connected in parallel to the 7Ω resistor. Find the total resistance of the two of them:
[tex]\begin{gathered} \frac{1}{\frac{1}{14}+\frac{1}{7}} \\ \\ \frac{1}{\frac{3}{14}}=\frac{14}{3} \\ \\ 4.67Ω \end{gathered}[/tex]
The equivalent resistance is the total resistance of the 6Ω resistor and the 4.67Ω resistance. Since they are connected in series, find the sum:
[tex]\begin{gathered} 6+4.67 \\ \\ 10.67Ω \end{gathered}[/tex]
That is the equivalent resistance.
