In order to find the direction we can use the next formula
[tex]\tan (\theta)=\frac{Cy}{Cx}[/tex]
we are looking for theta therefore we need to isolate it
[tex]\theta=\tan ^{-1}(\frac{Cy}{Cx})=\tan ^{-1}(\frac{-88.2}{-105})=40.03[/tex]
then because both components are negative me need to add 180 in order to find the direction of the vector
[tex]\text{direction}=40.03+180=220.03\text{\degree}[/tex]
