Here we have the expression:
[tex](3x^3y^{-2})^2[/tex]We want to find its value when x = -2 and y = 5. For this, we could replace the value of each variable:
[tex](3\cdot(-2)^3(5)^{-2})^2[/tex]Remember that:
[tex]\begin{gathered} (-2)^3=(-2)(-2)(-2)=-8 \\ \\ (5)^{-2}=\frac{1}{5^2}=\frac{1}{25} \end{gathered}[/tex]Replacing these values:
[tex](3\cdot(-8)(\frac{1}{25}))^2=(-\frac{24}{25})^2=\frac{576}{625}=0.9216[/tex]Which is the same that:
[tex]\frac{3^2(-2)^6}{5^4}[/tex]So the correct option is A.
