Given:
The height of the building, h=180 m
The initial velocity of the stone, u=0 m/s
To find:
The time it takes for the stone to reach the ground.
Explanation:
From the equation of motion,
[tex]h=ut+\frac{1}{2}gt^2[/tex]
Where t is the time it takes for the stone to reach the ground and g is the acceleration due to gravity.
On substituting the known values,
[tex]\begin{gathered} 180=0+\frac{1}{2}\times10\times t^2 \\ t=\sqrt{\frac{180\times2}{10}} \\ =6\text{ s} \end{gathered}[/tex]
Final answer:
The time it takes for the stone to reach the ground is 6 s.
