Given[tex]x^2-2x-10=0[/tex]Solution
[tex]x^2-2x-10=0[/tex]
Keep x terms on the left and move the constant to the right side by adding it on both sides
[tex]x^2-2x=10[/tex]
Take half of the x term and square it
[tex](-2\times\frac{1}{2})^2=1[/tex]
Then add the result to both sides
[tex]x^2-2x+1=10+11[/tex]
Rewrite the perfect square on the left
[tex](x-1)^2=10+1[/tex]
and combine terms on the right
[tex](x-1)^2=11[/tex]
Take the square root of both sides
[tex]\begin{gathered} x-1=\pm\sqrt{11} \\ x=1\pm\sqrt{11} \\ \end{gathered}[/tex]
simplify
[tex]\begin{gathered} x=4.32\text{ \lparen nearest 0.01\rparen} \\ x=-2.32(nearest\text{ 0.01\rparen} \end{gathered}[/tex]The final answer
