Question 14www3: HW 8-9 (Due August 3)0/1 pt10 DetailsHW 8-Acids and BasFollow these steps to write the balanced chemical equation for the reaction between acetic acid and sodiumhydroxide.1. Start by writing the proper names of the products below (separated by a + sign).Acetic acid + Sodium hydroxide →2. Next, write the full, balanced molecular equation with the correct chemical formulas, includingcoefficients.3. Finally, write the net ionic equation for this reaction below, including ionic charges.

Question

30-10-2022
Chemistry

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Question 14www3: HW 8-9 (Due August 3)0/1 pt10 DetailsHW 8-Acids and BasFollow these steps to write the balanced chemical equation for the reaction between acetic acid and sodiumhydroxide.1. Start by writing the proper names of the products below (separated by a + sign).Acetic acid + Sodium hydroxide →2. Next, write the full, balanced molecular equation with the correct chemical formulas, includingcoefficients.3. Finally, write the net ionic equation for this reaction below, including ionic charges.

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RodrigoA683980 RodrigoA683980 · Answer 1 · 2022-10-30T22:42:17+01:00

Answer

1. Acetic acid + Sodium hydroxide → Sodium Acetate + Water

2. CH₃COOH + NaOH → CH₃COONa + H₂O

3. CH₃COOH + OH⁻ → CH₃COO⁻ + H₂O

Explanation

1. The proper names of the products for the reaction between acetic acid and sodium hydroxide are given below (separated by a + sign).

Acetic acid + Sodium hydroxide → Sodium Acetate + Water

2. The full, balanced molecular equation with the correct chemical formulas, including coefficients is:

CH₃COOH + NaOH → CH₃COONa + H₂O

3. Finally, the net ionic equation for this reaction is below, including ionic charges.

Strong bases are considered strong electrolytes and will dissociate completely. This means that NaOH will split apart in the net ionic equation. Weak acids only dissociate partially and are not considered to split apart into ions when writing net ionic equations.

CH₃COOH + Na⁺ + OH⁻ → CH₃COO⁻ + Na⁺ + H₂O

Cross the spectator ions, we have:

CH₃COOH + OH⁻ → CH₃COO⁻ + H₂O