We can solve this using the formula below:
[tex]A=\frac{1}{2}(a+b)h[/tex]
where
A is the area
a and b are the base
h is the height
From the figure given,
a= 2
b = 5 2/3
h=4 1/3
substitute the values into the formula
[tex]A=\frac{1}{2}(2\text{ + 5}\frac{2}{3})\text{ }\times\text{4}\frac{1}{3}[/tex][tex]=\frac{1}{2}(2+\frac{17}{3})\times\frac{13}{3}[/tex][tex]=\frac{1}{2}(\frac{6+17}{3})\times\frac{13}{3}[/tex][tex]=\frac{1}{2}(\frac{23}{3})\times\frac{13}{3}[/tex][tex]=\frac{1\times23\times13}{2\times3\times3}[/tex][tex]=\frac{299}{18}[/tex][tex]=16\text{ }\frac{11}{18}ft^2[/tex]
