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A population of bacteria is growing according to the equation P(t)=600e0.03t . In how many years will the population will exceed 708? Round your answer to one decimal place.t =

Respuesta :

Given

[tex]P=600e^{0.03t}[/tex]

Find

time,t

Explaination

[tex]\begin{gathered} P=600e^{0.03t} \\ 708=600e^{0.03t} \\ 1.18=e^{0.03t} \end{gathered}[/tex]

Taking log on both sides

[tex]\begin{gathered} ln(1.18)=0.03t \\ 0.165514438=0.03t \\ t=5.5\text{ sec} \end{gathered}[/tex]

Final Answer

t = 5.5 sec