two airplanes leave an airport at the same time and travel in opposite direction. one plane travels 67 km/h slower than the other. if the two planes are 16,281 kilometers apart after 9 hours what is the rate of each plane

Respuesta :

The slower plane travels at x km/h. The faster plane travels at (x+67) km/h

The speed of separation is the sum of the speeds, (2x+67) km/h

They are 16281 km after 9 hours of travel.

speed = distance/time

[tex]\begin{gathered} 2x+67=\frac{16281}{9} \\ 2x+67=1809 \\ 2x+67-67=1809-67 \\ 2x=1742 \\ \frac{2x}{2}=\frac{1742}{2} \\ x=871 \end{gathered}[/tex]

The slower plane travels at 871 km/h

[tex]x+67=871+67=938[/tex]

The faster plane travels at 938 km/h