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A 435 mL solution was made by mixing 201 mL of cyclohexane, Which has a density of 0.78 g/mL, and 257 mL of toluene, Which has a density of 0.87 g/mL. Calculate the volume percentage of the cyclohexane in the solution. Be sure and answer has right number of significant digits.

A 435 mL solution was made by mixing 201 mL of cyclohexane Which has a density of 078 gmL and 257 mL of toluene Which has a density of 087 gmL Calculate the vol class=

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Answer:

[tex]46.2\text{ \%}[/tex]

Explanation:

Here, we want to calculate the volume percentage of cyclohexane in the solution

Mathematically, we have this as:

[tex]\frac{volume\text{ of cyclohexane}}{\text{volume of solution}}\times\text{ 100\%}[/tex]

Thus, we have the volume percentage as follows:

[tex]\frac{201}{435}\times\text{ 100 \% = 46.2 \% }[/tex]

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