10) We have to calculate the x and y intercepts for the line and graph the line:
[tex]-5x+y=-10[/tex]
The x-intercept corresponds to the point where y = 0, so we can calculate it as:
[tex]\begin{gathered} -5x+0=-10 \\ -5x=-10 \\ x=\frac{-10}{-5} \\ x=2 \end{gathered}[/tex]
The y-intercept corresponds to the point where x = 0, so we can calculate it as:
[tex]\begin{gathered} -5(0)+y=-10 \\ y=-10 \end{gathered}[/tex]
With the intercepts, we have two points: (2,0) and (0,-10) and we can use them to graph as:
11) We have to calculate the x and y intercepts for the line and graph the line:
[tex]-3x-6y=12[/tex]
The x-intercept is:
[tex]\begin{gathered} -3x-6(0)=12 \\ -3x=12 \\ x=\frac{12}{-3} \\ x=-4 \end{gathered}[/tex]
The y-intercept is:
[tex]\begin{gathered} -3(0)-6y=12 \\ -6y=12 \\ y=\frac{12}{-6} \\ y=-2 \end{gathered}[/tex]
Then, knowing the intercepts, we know the points (-4,0) and (0,-2) and we can graph the line as:
