Answer:
38.47 m
Explanation:
To find the height of the building, we will use the following equation
[tex]y_f=y_i+v_{iy}t+\frac{1}{2}at^2[/tex]Where yf is the final height, yi is the initial height, viy is the initial vertical velocity, t is the time, and a is the acceleration due to gravity.
If the brick is in flight for 3.1 s, we can say that when t = 3.1s, yf = 0 m. So, replacing
viy = (16 m/s)sin(10) = 2.78 m/s
a = -9.8 m/s²
we get
[tex]0=y_i+2.78(3.1)+\frac{1}{2}(-9.8)(3.1)^2[/tex]Solving for yi
[tex]\begin{gathered} 0=y_i-38.48 \\ y_i=38.48\text{ m} \end{gathered}[/tex]Therefore, the height of the building is 38.48 m
