4. A train travels a distance of 2650 kilometers. If the train left the station at 2:00 PM andarrived at its destination at 9:00 PM, what was its average speed? (Express your answer in m/s)/con

Respuesta :

Given,

The distance travelled by train, d=2650 km=2650×10³ m

The time interval in which the train covers the total distance, t=9.00-2.00=7.00 hrs

That is, t=7×3600 s=25200 s

The average speed is given by the ratio of total distance travelled to the total time duration.

That is,

[tex]s=\frac{d}{t}[/tex]

On substituting the known values,

[tex]\begin{gathered} s=\frac{2650\times10^3}{25200} \\ =105.16\text{ m/s} \end{gathered}[/tex]

Thus the average speed of the train is 105.16 m/s