ANSWER and EXPLANATION
We want to identify the parameters of the line in the electromagnetic spectrum.
The wavelength of line c is given as 486.13 nanometers. Converting this to meters, we have that the wavelength of line c is:
[tex]\begin{gathered} \lambda=486.13*10^{-9} \\ \lambda=4.86E-7\text{ }m \end{gathered}[/tex]To find the frequency of line c, apply the relationship between the velocity of light and wavelength:
[tex]f=\frac{c}{\lambda}[/tex]where c = velocity of light in a vacuum
f = frequency of the light
Hence, the frequency of line c is:
[tex]\begin{gathered} f=\frac{3.00*10^8}{4.85*10^{-7}} \\ f=6.19E14\text{ }Hz \end{gathered}[/tex]The velocity of light in a vacuum is given by:
[tex]c=3.00E8\text{ }m\/s[/tex]The energy of the line can be found using the formula:
[tex]E=hf[/tex]where E = energy
h = Planck's constant = 6.63E-34 Js
Hence, the energy of line c is:
[tex]\begin{gathered} E=6.63*10^{-34}*6.19*10^{14} \\ E=4.10E-19\text{ }J \end{gathered}[/tex]Those are the answers.
