As the events are independent, taking X as the event that the first coin is a nickel and Y the event that the second coin is a quarter. The probability is
[tex]P(X\text{ and Y)}=P(X)\cdot P(Y)[/tex]So in this case we have that
[tex]P(X\text{ and Y)}=P(X)\cdot P(Y)=\frac{4}{13}\cdot\frac{2}{12}=\frac{8}{156}=\frac{2}{39}[/tex]