The area of a triangle is 124 square units. What would its new area be if its base was half as long, and its height was three times as long?thank you ! :)

The area of a triangle is given by the following formula:
[tex]A=\frac{bh}{2},[/tex]where b= base, and h=height.
Now, if we multiply b by 1/2, and h by 3, we get:
[tex]\frac{b(\frac{1}{2})h(3)}{2}=\frac{3bh}{2(2)}=\frac{3}{2}\frac{bh}{2}=\frac{3}{2}A.[/tex]Therefore, if A=124 square units, the new area would be:
[tex]\frac{3}{2}A=\frac{3}{2}(124u^2)=186u^2.[/tex]