3x³
1) Evaluating that radical expression, we have:
Notice that we can rewrite that, under one and only radical, and then divide 81 by 3 and subtract the exponents (1 from 10)
And then, rewrite that radical as a power
[tex]\frac{\sqrt[3]{81x^{10}}}{\sqrt[3]{3x}}=\sqrt[3]{\frac{81x^{10}}{3\cdot x^{}}}=\sqrt[3]{27x^9^{}}=(27x^9)^{\frac{1}{3}}=3x^3[/tex]
2) As the cubic root of 27 is 3 and 9 times 1/3 is 3 we can write the solution as 3x³
3) Hence, that's the answer
