A honeybee sitting on a tulip wanted to fly to a daffodil located 100 meters due east. Although the honeybee flew in a straight line, it mistakenly flew in a direction 5° south of east. When the bee was directly south of the daffodil, how many meters from the bee was the daffodil? Enter your answer to 2 decimal places.

A honeybee sitting on a tulip wanted to fly to a daffodil located 100 meters due east Although the honeybee flew in a straight line it mistakenly flew in a dire class=

Respuesta :

Let's begin by listing out the given information:

Let the initial location of the honeybee be represented as B

Let the location of the honeybee be represented as C

Let the location of the daffodil be represented as D

[tex]\begin{gathered} BC(adjacent)=100m \\ \angle B=5^{\circ} \\ CD(opposite)=? \end{gathered}[/tex]

We will calculate for CD using the Trigonometric ratio (SOHCAHTOA). We will use TOA:

[tex]\begin{gathered} Tan\theta=\frac{opposite}{adjacent}=\frac{CD}{BD} \\ \theta=5^{\circ},BD=100m \\ Tan5^{\circ}=\frac{CD}{100} \\ CD=100\cdot Tan5^{\circ} \\ CD=8.78\approx8.8 \\ CD=8.8m \end{gathered}[/tex]